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1431121313 = 4333281891
BaseRepresentation
bin101010101001101…
…0010110110100001
310200201220111101002
41111103102312201
510412331340223
6354001521345
750315221226
oct12523226641
93621814332
101431121313
11674915696
1233b343255
1319a656c5b
14d80d394d
1585990e28
hex554d2da1

1431121313 has 4 divisors (see below), whose sum is σ = 1464403248. Its totient is φ = 1397839380.

The previous prime is 1431121301. The next prime is 1431121333. The reversal of 1431121313 is 3131211341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431121313 - 24 = 1431121297 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431121333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16640903 + ... + 16640988.

It is an arithmetic number, because the mean of its divisors is an integer number (366100812).

Almost surely, 21431121313 is an apocalyptic number.

It is an amenable number.

1431121313 is a deficient number, since it is larger than the sum of its proper divisors (33281935).

1431121313 is an equidigital number, since it uses as much as digits as its factorization.

1431121313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33281934.

The product of its digits is 216, while the sum is 20.

The square root of 1431121313 is about 37830.1640625573. The cubic root of 1431121313 is about 1126.9175692724.

Adding to 1431121313 its reverse (3131211341), we get a palindrome (4562332654).

The spelling of 1431121313 in words is "one billion, four hundred thirty-one million, one hundred twenty-one thousand, three hundred thirteen".

Divisors: 1 43 33281891 1431121313