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143112441491 is a prime number
BaseRepresentation
bin1000010101001000101…
…0101000111010010011
3111200101202022021210222
42011102022220322103
54321043241111431
6145424524143255
713224313452515
oct2052212507223
9450352267728
10143112441491
115576a273538
12238a0097b2b
1310659654c56
146cd8b43bb5
153ac90c657b
hex21522a8e93

143112441491 has 2 divisors, whose sum is σ = 143112441492. Its totient is φ = 143112441490.

The previous prime is 143112441413. The next prime is 143112441517. The reversal of 143112441491 is 194144211341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143112441491 - 214 = 143112425107 is a prime.

It is a super-3 number, since 3×1431124414913 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (143111441491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71556220745 + 71556220746.

It is an arithmetic number, because the mean of its divisors is an integer number (71556220746).

Almost surely, 2143112441491 is an apocalyptic number.

143112441491 is a deficient number, since it is larger than the sum of its proper divisors (1).

143112441491 is an equidigital number, since it uses as much as digits as its factorization.

143112441491 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824, while the sum is 35.

The spelling of 143112441491 in words is "one hundred forty-three billion, one hundred twelve million, four hundred forty-one thousand, four hundred ninety-one".