Base | Representation |
---|---|
bin | 1000010101001000101… |
… | …0101000111010010011 |
3 | 111200101202022021210222 |
4 | 2011102022220322103 |
5 | 4321043241111431 |
6 | 145424524143255 |
7 | 13224313452515 |
oct | 2052212507223 |
9 | 450352267728 |
10 | 143112441491 |
11 | 5576a273538 |
12 | 238a0097b2b |
13 | 10659654c56 |
14 | 6cd8b43bb5 |
15 | 3ac90c657b |
hex | 21522a8e93 |
143112441491 has 2 divisors, whose sum is σ = 143112441492. Its totient is φ = 143112441490.
The previous prime is 143112441413. The next prime is 143112441517. The reversal of 143112441491 is 194144211341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143112441491 - 214 = 143112425107 is a prime.
It is a super-3 number, since 3×1431124414913 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (143111441491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71556220745 + 71556220746.
It is an arithmetic number, because the mean of its divisors is an integer number (71556220746).
Almost surely, 2143112441491 is an apocalyptic number.
143112441491 is a deficient number, since it is larger than the sum of its proper divisors (1).
143112441491 is an equidigital number, since it uses as much as digits as its factorization.
143112441491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 35.
The spelling of 143112441491 in words is "one hundred forty-three billion, one hundred twelve million, four hundred forty-one thousand, four hundred ninety-one".
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