Base | Representation |
---|---|
bin | 10100110100110110000… |
… | …100110011110011100011 |
3 | 12001211000000002201120120 |
4 | 110310312010303303203 |
5 | 141421424110340003 |
6 | 3013241435211323 |
7 | 205252524451161 |
oct | 24646604636343 |
9 | 5054000081516 |
10 | 1431131340003 |
11 | 501a37371862 |
12 | 1b1442ba6b43 |
13 | a4c554a3811 |
14 | 4d3a4dd0231 |
15 | 27361260853 |
hex | 14d36133ce3 |
1431131340003 has 8 divisors (see below), whose sum is σ = 1908432628416. Its totient is φ = 953958805800.
The previous prime is 1431131339983. The next prime is 1431131340017. The reversal of 1431131340003 is 3000431311341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1431131340003 - 232 = 1426836372707 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1431131340403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32162613 + ... + 32207078.
It is an arithmetic number, because the mean of its divisors is an integer number (238554078552).
Almost surely, 21431131340003 is an apocalyptic number.
1431131340003 is a deficient number, since it is larger than the sum of its proper divisors (477301288413).
1431131340003 is an equidigital number, since it uses as much as digits as its factorization.
1431131340003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64377105.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1431131340003 its reverse (3000431311341), we get a palindrome (4431562651344).
The spelling of 1431131340003 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-one million, three hundred forty thousand, three".
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