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14311314022033 = 75509093711091
BaseRepresentation
bin1101000001000001110011…
…0010011101111010010001
31212200011000002011211222201
43100100130302131322101
53333434032342201113
650234305451003201
73004646463026050
oct320203462357221
955604002154881
1014311314022033
114618437741116
121731766139501
137ca721a77442
14376958064397
1519c40b9c9cdd
hexd041cc9de91

14311314022033 has 8 divisors (see below), whose sum is σ = 16355821549760. Its totient is φ = 12266815018320.

The previous prime is 14311314021997. The next prime is 14311314022073. The reversal of 14311314022033 is 33022041311341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14311314022033 - 233 = 14302724087441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14311314021992 and 14311314022010.

It is not an unprimeable number, because it can be changed into a prime (14311314022073) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2000818 + ... + 5711908.

It is an arithmetic number, because the mean of its divisors is an integer number (2044477693720).

Almost surely, 214311314022033 is an apocalyptic number.

It is an amenable number.

14311314022033 is a deficient number, since it is larger than the sum of its proper divisors (2044507527727).

14311314022033 is an equidigital number, since it uses as much as digits as its factorization.

14311314022033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4262007.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 14311314022033 its reverse (33022041311341), we get a palindrome (47333355333374).

The spelling of 14311314022033 in words is "fourteen trillion, three hundred eleven billion, three hundred fourteen million, twenty-two thousand, thirty-three".

Divisors: 1 7 550909 3711091 3856363 25977637 2044473431719 14311314022033