Base | Representation |
---|---|
bin | 1101000001000001110101… |
… | …1001110000001001000001 |
3 | 1212200011000210120001120210 |
4 | 3100100131121300021001 |
5 | 3333434043011222241 |
6 | 50234310455424333 |
7 | 3004646646410160 |
oct | 320203531601101 |
9 | 55604023501523 |
10 | 14311324320321 |
11 | 46184425353a6 |
12 | 17317696850a9 |
13 | 7ca723c419c2 |
14 | 3769595853d7 |
15 | 19c40c861316 |
hex | d041d670241 |
14311324320321 has 32 divisors (see below), whose sum is σ = 21817319231488. Its totient is φ = 8174305278720.
The previous prime is 14311324320277. The next prime is 14311324320329. The reversal of 14311324320321 is 12302342311341.
It is not a de Polignac number, because 14311324320321 - 230 = 14310250578497 is a prime.
It is a super-2 number, since 2×143113243203212 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14311324320329) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 933481626 + ... + 933496956.
It is an arithmetic number, because the mean of its divisors is an integer number (681791225984).
Almost surely, 214311324320321 is an apocalyptic number.
It is an amenable number.
14311324320321 is a deficient number, since it is larger than the sum of its proper divisors (7505994911167).
14311324320321 is a wasteful number, since it uses less digits than its factorization.
14311324320321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31981.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 14311324320321 its reverse (12302342311341), we get a palindrome (26613666631662).
The spelling of 14311324320321 in words is "fourteen trillion, three hundred eleven billion, three hundred twenty-four million, three hundred twenty thousand, three hundred twenty-one".
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