Base | Representation |
---|---|
bin | 10100110100110110010… |
… | …100000000100010100001 |
3 | 12001211000021121011000220 |
4 | 110310312110000202201 |
5 | 141421431120334241 |
6 | 3013242100433253 |
7 | 205252603354233 |
oct | 24646624004241 |
9 | 5054007534026 |
10 | 1431135324321 |
11 | 501a3964328a |
12 | 1b14443a8829 |
13 | a4c5626a1c1 |
14 | 4d3a574a253 |
15 | 2736179b166 |
hex | 14d365008a1 |
1431135324321 has 4 divisors (see below), whose sum is σ = 1908180432432. Its totient is φ = 954090216212.
The previous prime is 1431135324299. The next prime is 1431135324361. The reversal of 1431135324321 is 1234235311341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1431135324321 - 226 = 1431068215457 is a prime.
It is a super-2 number, since 2×14311353243212 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1431135324361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238522554051 + ... + 238522554056.
It is an arithmetic number, because the mean of its divisors is an integer number (477045108108).
Almost surely, 21431135324321 is an apocalyptic number.
It is an amenable number.
1431135324321 is a deficient number, since it is larger than the sum of its proper divisors (477045108111).
1431135324321 is an equidigital number, since it uses as much as digits as its factorization.
1431135324321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 477045108110.
The product of its digits is 25920, while the sum is 33.
The spelling of 1431135324321 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-five million, three hundred twenty-four thousand, three hundred twenty-one".
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