14311421433 has 12 divisors (see below), whose sum is σ = 21760056240. Its totient is φ = 9038792376.

The previous prime is 14311421431. The next prime is 14311421441. The reversal of 14311421433 is 33412411341.

14311421433 is a `hidden beast` number, since 1 + 431 + 14 + 214 + 3 + 3 = 666.

It is not a de Polignac number, because 14311421433 - 2¹ = 14311421431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14311421397 and 14311421406.

It is not an unprimeable number, because it can be changed into a prime (14311421431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 41846091 + ... + 41846432.

It is an arithmetic number, because the mean of its divisors is an integer number (1813338020).

Almost surely, 2^14311421433 is an apocalyptic number.

It is an amenable number.

14311421433 is a deficient number, since it is larger than the sum of its proper divisors (7448634807).

14311421433 is a wasteful number, since it uses less digits than its factorization.

14311421433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83692548 (or 83692545 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 14311421433 its reverse (33412411341), we get a palindrome (47723832774).

The spelling of 14311421433 in words is "fourteen billion, three hundred eleven million, four hundred twenty-one thousand, four hundred thirty-three".