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143114240240113 is a prime number
BaseRepresentation
bin100000100010100101100001…
…011100111010100111110001
3200202201120212110200022100111
4200202211201130322213301
5122224240431000140423
61224213435131221321
742100443200412532
oct4042454134724761
9622646773608314
10143114240240113
11416674546a91aa
12140745b95a7841
1361b17cc0650cc
14274aaa25b6689
151182ae320560d
hex82296173a9f1

143114240240113 has 2 divisors, whose sum is σ = 143114240240114. Its totient is φ = 143114240240112.

The previous prime is 143114240240033. The next prime is 143114240240171. The reversal of 143114240240113 is 311042042411341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119558632198369 + 23555608041744 = 10934287^2 + 4853412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143114240240113 is a prime.

It is not a weakly prime, because it can be changed into another prime (143114240243113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71557120120056 + 71557120120057.

It is an arithmetic number, because the mean of its divisors is an integer number (71557120120057).

Almost surely, 2143114240240113 is an apocalyptic number.

It is an amenable number.

143114240240113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143114240240113 is an equidigital number, since it uses as much as digits as its factorization.

143114240240113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 143114240240113 its reverse (311042042411341), we get a palindrome (454156282651454).

The spelling of 143114240240113 in words is "one hundred forty-three trillion, one hundred fourteen billion, two hundred forty million, two hundred forty thousand, one hundred thirteen".