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14312002405122 = 232795111244729
BaseRepresentation
bin1101000001000100010111…
…0100011100001100000010
31212200012210001111100001200
43100101011310130030002
53333441440103430442
650234502041242030
73005002522134612
oct320210564341402
955605701440050
1014312002405122
114618760276564
121731918793316
137ca80157a006
143769c1656a42
1519c44c15534c
hexd0445d1c302

14312002405122 has 12 divisors (see below), whose sum is σ = 31009338544470. Its totient is φ = 4770667468368.

The previous prime is 14312002405087. The next prime is 14312002405159. The reversal of 14312002405122 is 22150420021341.

14312002405122 is a `hidden beast` number, since 1 + 4 + 3 + 120 + 0 + 24 + 0 + 512 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 14050195192881 + 261807212241 = 3748359^2 + 511671^2 .

It is a super-2 number, since 2×143120024051222 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 397555622347 + ... + 397555622382.

Almost surely, 214312002405122 is an apocalyptic number.

14312002405122 is an abundant number, since it is smaller than the sum of its proper divisors (16697336139348).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14312002405122 is a wasteful number, since it uses less digits than its factorization.

14312002405122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 795111244737 (or 795111244734 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 27.

Adding to 14312002405122 its reverse (22150420021341), we get a palindrome (36462422426463).

The spelling of 14312002405122 in words is "fourteen trillion, three hundred twelve billion, two million, four hundred five thousand, one hundred twenty-two".

Divisors: 1 2 3 6 9 18 795111244729 1590222489458 2385333734187 4770667468374 7156001202561 14312002405122