143120041 has 2 divisors, whose sum is σ = 143120042. Its totient is φ = 143120040.

The previous prime is 143120011. The next prime is 143120051. The reversal of 143120041 is 140021341.

143120041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115777600 + 27342441 = 10760^2 + 5229^2 .

It is an emirp because it is prime and its reverse (140021341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143120041 - 2⁵ = 143120009 is a prime.

It is a super-2 number, since 2×143120041² = 40966692271683362, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143119997 and 143120024.

It is not a weakly prime, because it can be changed into another prime (143120011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560020 + 71560021.

It is an arithmetic number, because the mean of its divisors is an integer number (71560021).

Almost surely, 2^143120041 is an apocalyptic number.

It is an amenable number.

143120041 is a deficient number, since it is larger than the sum of its proper divisors (1).

143120041 is an equidigital number, since it uses as much as digits as its factorization.

143120041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 143120041 is about 11963.2788565677. The cubic root of 143120041 is about 523.0784369561.

Adding to 143120041 its reverse (140021341), we get a palindrome (283141382).

The spelling of 143120041 in words is "one hundred forty-three million, one hundred twenty thousand, forty-one".