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14312043433 is a prime number
BaseRepresentation
bin11010101010001000…
…00111001110101001
31100221102122010200201
431111010013032221
5213302340342213
610324100432201
71014444235102
oct152504071651
940842563621
1014312043433
116084859076
1229350a8661
13147116566c
1499ab033a9
1558b7206dd
hex3551073a9

14312043433 has 2 divisors, whose sum is σ = 14312043434. Its totient is φ = 14312043432.

The previous prime is 14312043409. The next prime is 14312043437. The reversal of 14312043433 is 33434021341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14276187289 + 35856144 = 119483^2 + 5988^2 .

It is a cyclic number.

It is not a de Polignac number, because 14312043433 - 25 = 14312043401 is a prime.

It is not a weakly prime, because it can be changed into another prime (14312043437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156021716 + 7156021717.

It is an arithmetic number, because the mean of its divisors is an integer number (7156021717).

Almost surely, 214312043433 is an apocalyptic number.

It is an amenable number.

14312043433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312043433 is an equidigital number, since it uses as much as digits as its factorization.

14312043433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 14312043433 its reverse (33434021341), we get a palindrome (47746064774).

The spelling of 14312043433 in words is "fourteen billion, three hundred twelve million, forty-three thousand, four hundred thirty-three".