Base | Representation |
---|---|
bin | 11010101010001000… |
… | …00111001110101001 |
3 | 1100221102122010200201 |
4 | 31111010013032221 |
5 | 213302340342213 |
6 | 10324100432201 |
7 | 1014444235102 |
oct | 152504071651 |
9 | 40842563621 |
10 | 14312043433 |
11 | 6084859076 |
12 | 29350a8661 |
13 | 147116566c |
14 | 99ab033a9 |
15 | 58b7206dd |
hex | 3551073a9 |
14312043433 has 2 divisors, whose sum is σ = 14312043434. Its totient is φ = 14312043432.
The previous prime is 14312043409. The next prime is 14312043437. The reversal of 14312043433 is 33434021341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14276187289 + 35856144 = 119483^2 + 5988^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312043433 - 25 = 14312043401 is a prime.
It is not a weakly prime, because it can be changed into another prime (14312043437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156021716 + 7156021717.
It is an arithmetic number, because the mean of its divisors is an integer number (7156021717).
Almost surely, 214312043433 is an apocalyptic number.
It is an amenable number.
14312043433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312043433 is an equidigital number, since it uses as much as digits as its factorization.
14312043433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 14312043433 its reverse (33434021341), we get a palindrome (47746064774).
The spelling of 14312043433 in words is "fourteen billion, three hundred twelve million, forty-three thousand, four hundred thirty-three".
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