143121040410121 has 4 divisors (see below), whose sum is σ = 145136829711744. Its totient is φ = 141105251108500.

The previous prime is 143121040410107. The next prime is 143121040410143. The reversal of 143121040410121 is 121014040121341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143121040410121 - 2¹⁵ = 143121040377353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143121040410521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007894650705 + ... + 1007894650846.

It is an arithmetic number, because the mean of its divisors is an integer number (36284207427936).

Almost surely, 2^{143121040410121} is an apocalyptic number.

It is an amenable number.

143121040410121 is a deficient number, since it is larger than the sum of its proper divisors (2015789301623).

143121040410121 is an equidigital number, since it uses as much as digits as its factorization.

143121040410121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2015789301622.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 143121040410121 its reverse (121014040121341), we get a palindrome (264135080531462).

The spelling of 143121040410121 in words is "one hundred forty-three trillion, one hundred twenty-one billion, forty million, four hundred ten thousand, one hundred twenty-one".