1431212121 has 6 divisors (see below), whose sum is σ = 2067306410. Its totient is φ = 954141408.

The previous prime is 1431212093. The next prime is 1431212131. The reversal of 1431212121 is 1212121341.

1431212121 is a `hidden beast` number, since 1 + 431 + 21 + 212 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 838971225 + 592240896 = 28965^2 + 24336^2 .

It is not a de Polignac number, because 1431212121 - 2⁹ = 1431211609 is a prime.

It is a super-3 number, since 3×1431212121³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431212094 and 1431212103.

It is not an unprimeable number, because it can be changed into a prime (1431212131) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 79511776 + ... + 79511793.

Almost surely, 2^1431212121 is an apocalyptic number.

It is an amenable number.

1431212121 is a deficient number, since it is larger than the sum of its proper divisors (636094289).

1431212121 is a wasteful number, since it uses less digits than its factorization.

1431212121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159023575 (or 159023572 counting only the distinct ones).

The product of its digits is 96, while the sum is 18.

The square root of 1431212121 is about 37831.3642497862. The cubic root of 1431212121 is about 1126.9414039549.

Adding to 1431212121 its reverse (1212121341), we get a palindrome (2643333462).

The spelling of 1431212121 in words is "one billion, four hundred thirty-one million, two hundred twelve thousand, one hundred twenty-one".