Base | Representation |
---|---|
bin | 100000100010101100001110… |
… | …010010110101010001100010 |
3 | 200202202021102212221010020210 |
4 | 200202230032102311101202 |
5 | 122224400144331204214 |
6 | 1224221025104314550 |
7 | 42101116403145351 |
oct | 4042541622652142 |
9 | 622667385833223 |
10 | 143121435022434 |
11 | 4166a5069a16a0 |
12 | 14075a87012a56 |
13 | 61b23a781945b |
14 | 274b185d57998 |
15 | 1182db4b97b59 |
hex | 822b0e4b5462 |
143121435022434 has 32 divisors (see below), whose sum is σ = 319526924707584. Its totient is φ = 42361524107280.
The previous prime is 143121435022421. The next prime is 143121435022451. The reversal of 143121435022434 is 434220534121341.
It is a junction number, because it is equal to n+sod(n) for n = 143121435022392 and 143121435022401.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25215190084 + ... + 25215195759.
It is an arithmetic number, because the mean of its divisors is an integer number (9985216397112).
Almost surely, 2143121435022434 is an apocalyptic number.
143121435022434 is an abundant number, since it is smaller than the sum of its proper divisors (176405489685150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143121435022434 is a wasteful number, since it uses less digits than its factorization.
143121435022434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50430385902.
The product of its (nonzero) digits is 276480, while the sum is 39.
Adding to 143121435022434 its reverse (434220534121341), we get a palindrome (577341969143775).
The spelling of 143121435022434 in words is "one hundred forty-three trillion, one hundred twenty-one billion, four hundred thirty-five million, twenty-two thousand, four hundred thirty-four".
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