14312234113 has 2 divisors, whose sum is σ = 14312234114. Its totient is φ = 14312234112.

The previous prime is 14312234059. The next prime is 14312234117. The reversal of 14312234113 is 31143221341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8348842384 + 5963391729 = 91372^2 + 77223^2 .

It is a cyclic number.

It is not a de Polignac number, because 14312234113 - 2¹⁷ = 14312103041 is a prime.

It is not a weakly prime, because it can be changed into another prime (14312234117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156117056 + 7156117057.

It is an arithmetic number, because the mean of its divisors is an integer number (7156117057).

Almost surely, 2^14312234113 is an apocalyptic number.

It is an amenable number.

14312234113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312234113 is an equidigital number, since it uses as much as digits as its factorization.

14312234113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

Adding to 14312234113 its reverse (31143221341), we get a palindrome (45455455454).

The spelling of 14312234113 in words is "fourteen billion, three hundred twelve million, two hundred thirty-four thousand, one hundred thirteen".