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143124213019 is a prime number
BaseRepresentation
bin1000010101001011011…
…1100010110100011011
3111200102120110100022111
42011102313202310123
54321104244304034
6145430024333151
713224515511034
oct2052267426433
9450376410274
10143124213019
1155775983677
12238a40141b7
131065bc16c58
146cda529a8b
153aca14e364
hex2152de2d1b

143124213019 has 2 divisors, whose sum is σ = 143124213020. Its totient is φ = 143124213018.

The previous prime is 143124212999. The next prime is 143124213041. The reversal of 143124213019 is 910312421341.

143124213019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (910312421341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143124213019 - 225 = 143090658587 is a prime.

It is a super-2 number, since 2×1431242130192 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143124213119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562106509 + 71562106510.

It is an arithmetic number, because the mean of its divisors is an integer number (71562106510).

Almost surely, 2143124213019 is an apocalyptic number.

143124213019 is a deficient number, since it is larger than the sum of its proper divisors (1).

143124213019 is an equidigital number, since it uses as much as digits as its factorization.

143124213019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 143124213019 in words is "one hundred forty-three billion, one hundred twenty-four million, two hundred thirteen thousand, nineteen".