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14312770017353 is a prime number
BaseRepresentation
bin1101000001000111001110…
…0100101001100001001001
31212200021202112220002002022
43100101303210221201021
53334000023111023403
650235110142014225
73005030532546263
oct320216344514111
955607675802068
1014312770017353
1146190145a5a35
121731ab1877375
137ca8c4600132
14376a55590b33
1519c494730d38
hexd0473929849

14312770017353 has 2 divisors, whose sum is σ = 14312770017354. Its totient is φ = 14312770017352.

The previous prime is 14312770017239. The next prime is 14312770017361. The reversal of 14312770017353 is 35371007721341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14119159457209 + 193610560144 = 3757547^2 + 440012^2 .

It is a cyclic number.

It is not a de Polignac number, because 14312770017353 - 210 = 14312770016329 is a prime.

It is a super-2 number, since 2×143127700173532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14312770217353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156385008676 + 7156385008677.

It is an arithmetic number, because the mean of its divisors is an integer number (7156385008677).

Almost surely, 214312770017353 is an apocalyptic number.

It is an amenable number.

14312770017353 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312770017353 is an equidigital number, since it uses as much as digits as its factorization.

14312770017353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 370440, while the sum is 44.

Adding to 14312770017353 its reverse (35371007721341), we get a palindrome (49683777738694).

The spelling of 14312770017353 in words is "fourteen trillion, three hundred twelve billion, seven hundred seventy million, seventeen thousand, three hundred fifty-three".