Base | Representation |
---|---|
bin | 1101000001000111001110… |
… | …0100101001100001001001 |
3 | 1212200021202112220002002022 |
4 | 3100101303210221201021 |
5 | 3334000023111023403 |
6 | 50235110142014225 |
7 | 3005030532546263 |
oct | 320216344514111 |
9 | 55607675802068 |
10 | 14312770017353 |
11 | 46190145a5a35 |
12 | 1731ab1877375 |
13 | 7ca8c4600132 |
14 | 376a55590b33 |
15 | 19c494730d38 |
hex | d0473929849 |
14312770017353 has 2 divisors, whose sum is σ = 14312770017354. Its totient is φ = 14312770017352.
The previous prime is 14312770017239. The next prime is 14312770017361. The reversal of 14312770017353 is 35371007721341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14119159457209 + 193610560144 = 3757547^2 + 440012^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312770017353 - 210 = 14312770016329 is a prime.
It is a super-2 number, since 2×143127700173532 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14312770217353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156385008676 + 7156385008677.
It is an arithmetic number, because the mean of its divisors is an integer number (7156385008677).
Almost surely, 214312770017353 is an apocalyptic number.
It is an amenable number.
14312770017353 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312770017353 is an equidigital number, since it uses as much as digits as its factorization.
14312770017353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 370440, while the sum is 44.
Adding to 14312770017353 its reverse (35371007721341), we get a palindrome (49683777738694).
The spelling of 14312770017353 in words is "fourteen trillion, three hundred twelve billion, seven hundred seventy million, seventeen thousand, three hundred fifty-three".
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