Base | Representation |
---|---|
bin | 1101000001001000000110… |
… | …0001110000011001010001 |
3 | 1212200022100212102202010122 |
4 | 3100102001201300121101 |
5 | 3334001013024440423 |
6 | 50235145304040025 |
7 | 3005036404553030 |
oct | 320220141603121 |
9 | 55608325382118 |
10 | 14313004140113 |
11 | 4619124774918 |
12 | 1731b58163015 |
13 | 7ca930c73b03 |
14 | 376a786d6717 |
15 | 19c4aa07a8c8 |
hex | d0481870651 |
14313004140113 has 32 divisors (see below), whose sum is σ = 17349982244352. Its totient is φ = 11541685478400.
The previous prime is 14313004140103. The next prime is 14313004140137. The reversal of 14313004140113 is 31104140031341.
It is not a de Polignac number, because 14313004140113 - 28 = 14313004139857 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (14313004140103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 163583945 + ... + 163671417.
It is an arithmetic number, because the mean of its divisors is an integer number (542186945136).
Almost surely, 214313004140113 is an apocalyptic number.
It is an amenable number.
14313004140113 is a deficient number, since it is larger than the sum of its proper divisors (3036978104239).
14313004140113 is a wasteful number, since it uses less digits than its factorization.
14313004140113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104225.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 14313004140113 its reverse (31104140031341), we get a palindrome (45417144171454).
The spelling of 14313004140113 in words is "fourteen trillion, three hundred thirteen billion, four million, one hundred forty thousand, one hundred thirteen".
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