Base | Representation |
---|---|
bin | 1000010101001100111… |
… | …0001001110111010001 |
3 | 111200102222121110202111 |
4 | 2011103032021313101 |
5 | 4321112303440423 |
6 | 145430355345321 |
7 | 13224620055142 |
oct | 2052316116721 |
9 | 450388543674 |
10 | 143130140113 |
11 | 557792617a4 |
12 | 238a5bb2241 |
13 | 106602109cc |
14 | 6cdb22dac9 |
15 | 3aca92060d |
hex | 2153389dd1 |
143130140113 has 2 divisors, whose sum is σ = 143130140114. Its totient is φ = 143130140112.
The previous prime is 143130140099. The next prime is 143130140137. The reversal of 143130140113 is 311041031341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 142413400129 + 716739984 = 377377^2 + 26772^2 .
It is a cyclic number.
It is not a de Polignac number, because 143130140113 - 221 = 143128042961 is a prime.
It is not a weakly prime, because it can be changed into another prime (143130150113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71565070056 + 71565070057.
It is an arithmetic number, because the mean of its divisors is an integer number (71565070057).
Almost surely, 2143130140113 is an apocalyptic number.
It is an amenable number.
143130140113 is a deficient number, since it is larger than the sum of its proper divisors (1).
143130140113 is an equidigital number, since it uses as much as digits as its factorization.
143130140113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 143130140113 its reverse (311041031341), we get a palindrome (454171171454).
The spelling of 143130140113 in words is "one hundred forty-three billion, one hundred thirty million, one hundred forty thousand, one hundred thirteen".
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