Search a number
-
+
1431314011123 = 7454711920013
BaseRepresentation
bin10100110101000000111…
…101101001001111110011
312001211110201211101020121
4110311000331221033303
5141422312341323443
63013311522351111
7205260203233063
oct24650075511763
95054421741217
101431314011123
11502020499327
121b14941bb497
13a4c842a1439
144d3c13813a3
15273722e54ed
hex14d40f693f3

1431314011123 has 4 divisors (see below), whose sum is σ = 1431316676608. Its totient is φ = 1431311345640.

The previous prime is 1431314011097. The next prime is 1431314011151. The reversal of 1431314011123 is 3211104131341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1431314011123 is a prime.

It is a super-2 number, since 2×14313140111232 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431314011223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214536 + ... + 1705477.

It is an arithmetic number, because the mean of its divisors is an integer number (357829169152).

Almost surely, 21431314011123 is an apocalyptic number.

1431314011123 is a deficient number, since it is larger than the sum of its proper divisors (2665485).

1431314011123 is an equidigital number, since it uses as much as digits as its factorization.

1431314011123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2665484.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1431314011123 its reverse (3211104131341), we get a palindrome (4642418142464).

The spelling of 1431314011123 in words is "one trillion, four hundred thirty-one billion, three hundred fourteen million, eleven thousand, one hundred twenty-three".

Divisors: 1 745471 1920013 1431314011123