Base | Representation |
---|---|
bin | 1000010101001101010… |
… | …1010101011000111011 |
3 | 111200110010011002200021 |
4 | 2011103111111120323 |
5 | 4321113244203311 |
6 | 145430503551311 |
7 | 13224642054514 |
oct | 2052325253073 |
9 | 450403132607 |
10 | 143132022331 |
11 | 5577a327951 |
12 | 238a675b537 |
13 | 1066071c64c |
14 | 6cdb59da0b |
15 | 3acab93171 |
hex | 215355563b |
143132022331 has 4 divisors (see below), whose sum is σ = 143441163232. Its totient is φ = 142822881432.
The previous prime is 143132022317. The next prime is 143132022343. The reversal of 143132022331 is 133220231341.
143132022331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143132022331 - 213 = 143132014139 is a prime.
It is a super-2 number, since 2×1431320223312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 143132022296 and 143132022305.
It is not an unprimeable number, because it can be changed into a prime (143130022331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154569756 + ... + 154570681.
It is an arithmetic number, because the mean of its divisors is an integer number (35860290808).
Almost surely, 2143132022331 is an apocalyptic number.
143132022331 is a deficient number, since it is larger than the sum of its proper divisors (309140901).
143132022331 is an equidigital number, since it uses as much as digits as its factorization.
143132022331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 309140900.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 143132022331 its reverse (133220231341), we get a palindrome (276352253672).
The spelling of 143132022331 in words is "one hundred forty-three billion, one hundred thirty-two million, twenty-two thousand, three hundred thirty-one".
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