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14313323001 = 34771107667
BaseRepresentation
bin11010101010010001…
…11111100111111001
31100221112001010221010
431111020333213321
5213303202314001
610324144104133
71014461144445
oct152510774771
940845033833
1014313323001
11608555246a
122935605049
1314714c2bc3
1499ad57825
1558b8c48d6
hex35523f9f9

14313323001 has 4 divisors (see below), whose sum is σ = 19084430672. Its totient is φ = 9542215332.

The previous prime is 14313322981. The next prime is 14313323021. The reversal of 14313323001 is 10032331341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (14313322981) and next prime (14313323021).

It is not a de Polignac number, because 14313323001 - 29 = 14313322489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14313323021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385553831 + ... + 2385553836.

It is an arithmetic number, because the mean of its divisors is an integer number (4771107668).

Almost surely, 214313323001 is an apocalyptic number.

It is an amenable number.

14313323001 is a deficient number, since it is larger than the sum of its proper divisors (4771107671).

14313323001 is an equidigital number, since it uses as much as digits as its factorization.

14313323001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4771107670.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 14313323001 its reverse (10032331341), we get a palindrome (24345654342).

The spelling of 14313323001 in words is "fourteen billion, three hundred thirteen million, three hundred twenty-three thousand, one".

Divisors: 1 3 4771107667 14313323001