Base | Representation |
---|---|
bin | 1101000001001001100101… |
… | …1000011001101100110010 |
3 | 1212200100101202111001121021 |
4 | 3100102121120121230302 |
5 | 3334002323002403132 |
6 | 50235253121450054 |
7 | 3005052334322422 |
oct | 320223130315462 |
9 | 55610352431537 |
10 | 14313404341042 |
11 | 461930a667794 |
12 | 173204a1a092a |
13 | 7ca995b559b1 |
14 | 376ab5910482 |
15 | 19c4d027d997 |
hex | d0499619b32 |
14313404341042 has 4 divisors (see below), whose sum is σ = 21470106511566. Its totient is φ = 7156702170520.
The previous prime is 14313404341021. The next prime is 14313404341081. The reversal of 14313404341042 is 24014340431341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13221506827321 + 1091897513721 = 3636139^2 + 1044939^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14313404340989 and 14313404341007.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3578351085259 + ... + 3578351085262.
Almost surely, 214313404341042 is an apocalyptic number.
14313404341042 is a deficient number, since it is larger than the sum of its proper divisors (7156702170524).
14313404341042 is an equidigital number, since it uses as much as digits as its factorization.
14313404341042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7156702170523.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 14313404341042 its reverse (24014340431341), we get a palindrome (38327744772383).
The spelling of 14313404341042 in words is "fourteen trillion, three hundred thirteen billion, four hundred four million, three hundred forty-one thousand, forty-two".
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