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14313414212111 = 7181105239107347
BaseRepresentation
bin1101000001001001100111…
…1110000011101000001111
31212200100102110001120011102
43100102121332003220033
53334002333014241421
650235254113213315
73005052514244150
oct320223176035017
955610373046142
1014313414212111
114619315199aa3
12173205156123b
137ca997c00971
14376ab6d5d927
1519c4d107d60b
hexd0499f83a0f

14313414212111 has 16 divisors (see below), whose sum is σ = 16448873925120. Its totient is φ = 12200628615840.

The previous prime is 14313414212051. The next prime is 14313414212143. The reversal of 14313414212111 is 11121241431341.

It is not a de Polignac number, because 14313414212111 - 230 = 14312340470287 is a prime.

It is a super-2 number, since 2×143134142121112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14313414212171) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 133284140 + ... + 133391486.

It is an arithmetic number, because the mean of its divisors is an integer number (1028054620320).

Almost surely, 214313414212111 is an apocalyptic number.

14313414212111 is a deficient number, since it is larger than the sum of its proper divisors (2135459713009).

14313414212111 is a wasteful number, since it uses less digits than its factorization.

14313414212111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212774.

The product of its digits is 2304, while the sum is 29.

Adding to 14313414212111 its reverse (11121241431341), we get a palindrome (25434655643452).

The spelling of 14313414212111 in words is "fourteen trillion, three hundred thirteen billion, four hundred fourteen million, two hundred twelve thousand, one hundred eleven".

Divisors: 1 7 181 1267 105239 107347 736673 751429 19048259 19429807 133337813 136008649 11297090933 79079636531 2044773458873 14313414212111