Base | Representation |
---|---|
bin | 11010101010010010… |
… | …11000101000100011 |
3 | 1100221112020100110021 |
4 | 31111021120220203 |
5 | 213303214103233 |
6 | 10324150214311 |
7 | 1014462052222 |
oct | 152511305043 |
9 | 40845210407 |
10 | 14313425443 |
11 | 6085612429 |
12 | 2935654397 |
13 | 147152a715 |
14 | 99ad82cb9 |
15 | 58b8e4e2d |
hex | 355258a23 |
14313425443 has 8 divisors (see below), whose sum is σ = 14600435328. Its totient is φ = 14027043264.
The previous prime is 14313425419. The next prime is 14313425461. The reversal of 14313425443 is 34452431341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14313425443 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14313425399 and 14313425408.
It is not an unprimeable number, because it can be changed into a prime (14313425843) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110730 + ... + 202207.
It is an arithmetic number, because the mean of its divisors is an integer number (1825054416).
Almost surely, 214313425443 is an apocalyptic number.
14313425443 is a deficient number, since it is larger than the sum of its proper divisors (287009885).
14313425443 is an equidigital number, since it uses as much as digits as its factorization.
14313425443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 313853.
The product of its digits is 69120, while the sum is 34.
Adding to 14313425443 its reverse (34452431341), we get a palindrome (48765856784).
The spelling of 14313425443 in words is "fourteen billion, three hundred thirteen million, four hundred twenty-five thousand, four hundred forty-three".
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