14313434001131 has 4 divisors (see below), whose sum is σ = 14313465348912. Its totient is φ = 14313402653352.

The previous prime is 14313434001121. The next prime is 14313434001137. The reversal of 14313434001131 is 13110043431341.

14313434001131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14313434001131 - 2⁴² = 9915387490027 is a prime.

It is a super-2 number, since 2×14313434001131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14313434001094 and 14313434001103.

It is not an unprimeable number, because it can be changed into a prime (14313434001137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14978711 + ... + 15905616.

It is an arithmetic number, because the mean of its divisors is an integer number (3578366337228).

Almost surely, 2^{14313434001131} is an apocalyptic number.

14313434001131 is a deficient number, since it is larger than the sum of its proper divisors (31347781).

14313434001131 is an equidigital number, since it uses as much as digits as its factorization.

14313434001131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31347780.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 14313434001131 its reverse (13110043431341), we get a palindrome (27423477432472).

The spelling of 14313434001131 in words is "fourteen trillion, three hundred thirteen billion, four hundred thirty-four million, one thousand, one hundred thirty-one".