14314040403211 has 4 divisors (see below), whose sum is σ = 14314113174712. Its totient is φ = 14313967631712.

The previous prime is 14314040403163. The next prime is 14314040403239. The reversal of 14314040403211 is 11230404041341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14314040403211 is a prime.

It is a super-2 number, since 2×14314040403211² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14314040403211.

It is not an unprimeable number, because it can be changed into a prime (14314040403011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36089901 + ... + 36484366.

It is an arithmetic number, because the mean of its divisors is an integer number (3578528293678).

Almost surely, 2^{14314040403211} is an apocalyptic number.

14314040403211 is a deficient number, since it is larger than the sum of its proper divisors (72771501).

14314040403211 is an equidigital number, since it uses as much as digits as its factorization.

14314040403211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72771500.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 14314040403211 its reverse (11230404041341), we get a palindrome (25544444444552).

The spelling of 14314040403211 in words is "fourteen trillion, three hundred fourteen billion, forty million, four hundred three thousand, two hundred eleven".