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143143023323281 is a prime number
BaseRepresentation
bin100000100011000000010101…
…000011101010100010010001
3200202211100011102010102122211
4200203000111003222202101
5122230223402432321111
61224234555212432121
742102512362525102
oct4043002503524221
9622740142112584
10143143023323281
1141678684a31643
121407a0b0a78641
1361b4438291a77
14274c23316a3a9
15118372a0a1521
hex8230150ea891

143143023323281 has 2 divisors, whose sum is σ = 143143023323282. Its totient is φ = 143143023323280.

The previous prime is 143143023323269. The next prime is 143143023323323. The reversal of 143143023323281 is 182323320341341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143099492256400 + 43531066881 = 11962420^2 + 208641^2 .

It is an emirp because it is prime and its reverse (182323320341341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143143023323281 - 221 = 143143021226129 is a prime.

It is a super-2 number, since 2×1431430233232812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143143023333281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71571511661640 + 71571511661641.

It is an arithmetic number, because the mean of its divisors is an integer number (71571511661641).

Almost surely, 2143143023323281 is an apocalyptic number.

It is an amenable number.

143143023323281 is a deficient number, since it is larger than the sum of its proper divisors (1).

143143023323281 is an equidigital number, since it uses as much as digits as its factorization.

143143023323281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 143143023323281 in words is "one hundred forty-three trillion, one hundred forty-three billion, twenty-three million, three hundred twenty-three thousand, two hundred eighty-one".