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1431473738641 = 6401922360139
BaseRepresentation
bin10100110101001010011…
…110111101001110010001
312001211212212101101012121
4110311022132331032101
5141423124234114031
63013335430054241
7205264153006012
oct24651236751621
95054785341177
101431473738641
115020a2674a41
121b15197aa381
13a4cab3c7b6b
144d3d867d009
1527381347011
hex14d4a7bd391

1431473738641 has 4 divisors (see below), whose sum is σ = 1431496162800. Its totient is φ = 1431451314484.

The previous prime is 1431473738623. The next prime is 1431473738683. The reversal of 1431473738641 is 1468373741341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431473738641 - 25 = 1431473738609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431473738341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11116051 + ... + 11244088.

It is an arithmetic number, because the mean of its divisors is an integer number (357874040700).

Almost surely, 21431473738641 is an apocalyptic number.

It is an amenable number.

1431473738641 is a deficient number, since it is larger than the sum of its proper divisors (22424159).

1431473738641 is an equidigital number, since it uses as much as digits as its factorization.

1431473738641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22424158.

The product of its digits is 4064256, while the sum is 52.

The spelling of 1431473738641 in words is "one trillion, four hundred thirty-one billion, four hundred seventy-three million, seven hundred thirty-eight thousand, six hundred forty-one".

Divisors: 1 64019 22360139 1431473738641