Base | Representation |
---|---|
bin | 11010101010011111… |
… | …00011001100010011 |
3 | 1100221122021110100021 |
4 | 31111033203030103 |
5 | 213304122312210 |
6 | 10324245004311 |
7 | 1014511563013 |
oct | 152517431423 |
9 | 40848243307 |
10 | 14315041555 |
11 | 6086516661 |
12 | 29360b3697 |
13 | 14719751b9 |
14 | 99b283c43 |
15 | 58bb13bda |
hex | 3553e3313 |
14315041555 has 16 divisors (see below), whose sum is σ = 18072631584. Its totient is φ = 10870744320.
The previous prime is 14315041501. The next prime is 14315041561. The reversal of 14315041555 is 55514051341.
It is not a de Polignac number, because 14315041555 - 211 = 14315039507 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14315041555.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 936057 + ... + 951226.
It is an arithmetic number, because the mean of its divisors is an integer number (1129539474).
Almost surely, 214315041555 is an apocalyptic number.
14315041555 is a deficient number, since it is larger than the sum of its proper divisors (3757590029).
14315041555 is a wasteful number, since it uses less digits than its factorization.
14315041555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1887366.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 14315041555 its reverse (55514051341), we get a palindrome (69829092896).
The spelling of 14315041555 in words is "fourteen billion, three hundred fifteen million, forty-one thousand, five hundred fifty-five".
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