Base | Representation |
---|---|
bin | 10100110101001111010… |
… | …110011110010111110001 |
3 | 12001212002120001021011212 |
4 | 110311033112132113301 |
5 | 141423311140314301 |
6 | 3013351504245505 |
7 | 205266164065202 |
oct | 24651726362761 |
9 | 5055076037155 |
10 | 1431555401201 |
11 | 502134781262 |
12 | 1b1541010895 |
13 | a4cc22babc3 |
14 | 4d4054595a9 |
15 | 273885c84bb |
hex | 14d4f59e5f1 |
1431555401201 has 2 divisors, whose sum is σ = 1431555401202. Its totient is φ = 1431555401200.
The previous prime is 1431555401183. The next prime is 1431555401207. The reversal of 1431555401201 is 1021045551341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1008821368801 + 422734032400 = 1004401^2 + 650180^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1431555401201 is a prime.
It is not a weakly prime, because it can be changed into another prime (1431555401207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715777700600 + 715777700601.
It is an arithmetic number, because the mean of its divisors is an integer number (715777700601).
Almost surely, 21431555401201 is an apocalyptic number.
It is an amenable number.
1431555401201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431555401201 is an equidigital number, since it uses as much as digits as its factorization.
1431555401201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 1431555401201 in words is "one trillion, four hundred thirty-one billion, five hundred fifty-five million, four hundred one thousand, two hundred one".
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