Base | Representation |
---|---|
bin | 1101000001010010110101… |
… | …1110001000100000010011 |
3 | 1212200120210220120021120202 |
4 | 3100110231132020200103 |
5 | 3334022420022341233 |
6 | 50240343433525415 |
7 | 3005201033431325 |
oct | 320245536104023 |
9 | 55616726507522 |
10 | 14315888871443 |
11 | 461a3750651a5 |
12 | 173262227386b |
13 | 7caca07c9b23 |
14 | 376c6d895615 |
15 | 19c5c8450be8 |
hex | d052d788813 |
14315888871443 has 2 divisors, whose sum is σ = 14315888871444. Its totient is φ = 14315888871442.
The previous prime is 14315888871371. The next prime is 14315888871469. The reversal of 14315888871443 is 34417888851341.
It is a strong prime.
It is an emirp because it is prime and its reverse (34417888851341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14315888871443 - 210 = 14315888870419 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14315888871443.
It is not a weakly prime, because it can be changed into another prime (14315888871743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157944435721 + 7157944435722.
It is an arithmetic number, because the mean of its divisors is an integer number (7157944435722).
Almost surely, 214315888871443 is an apocalyptic number.
14315888871443 is a deficient number, since it is larger than the sum of its proper divisors (1).
14315888871443 is an equidigital number, since it uses as much as digits as its factorization.
14315888871443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 82575360, while the sum is 65.
The spelling of 14315888871443 in words is "fourteen trillion, three hundred fifteen billion, eight hundred eighty-eight million, eight hundred seventy-one thousand, four hundred forty-three".
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