Search a number
-
+
143160354912457 is a prime number
BaseRepresentation
bin100000100011010000011110…
…000110011011100011001001
3200202212222220021120101102001
4200203100132012123203021
5122231014401324144312
61224250543100511001
742103665023563441
oct4043203606334311
9622788807511361
10143160354912457
1141684a69190063
121408152924b461
1361b5c6ab9338c
14274cdd8cc3121
151183de1927057
hex82341e19b8c9

143160354912457 has 2 divisors, whose sum is σ = 143160354912458. Its totient is φ = 143160354912456.

The previous prime is 143160354912409. The next prime is 143160354912461. The reversal of 143160354912457 is 754219453061341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104385025176201 + 38775329736256 = 10216899^2 + 6226984^2 .

It is a cyclic number.

It is not a de Polignac number, because 143160354912457 - 27 = 143160354912329 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143160354912398 and 143160354912407.

It is not a weakly prime, because it can be changed into another prime (143160354919457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71580177456228 + 71580177456229.

It is an arithmetic number, because the mean of its divisors is an integer number (71580177456229).

Almost surely, 2143160354912457 is an apocalyptic number.

It is an amenable number.

143160354912457 is a deficient number, since it is larger than the sum of its proper divisors (1).

143160354912457 is an equidigital number, since it uses as much as digits as its factorization.

143160354912457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10886400, while the sum is 55.

The spelling of 143160354912457 in words is "one hundred forty-three trillion, one hundred sixty billion, three hundred fifty-four million, nine hundred twelve thousand, four hundred fifty-seven".