Base | Representation |
---|---|
bin | 100000100011010000100010… |
… | …001000010101100111101001 |
3 | 200202220000001222210021100001 |
4 | 200203100202020111213221 |
5 | 122231020021131140241 |
6 | 1224250553513543001 |
7 | 42103666504341022 |
oct | 4043204210254751 |
9 | 622800058707301 |
10 | 143160422521321 |
11 | 41684aa3368657 |
12 | 14081547a14a61 |
13 | 61b5c7bba571a |
14 | 274d003c81c49 |
15 | 1183de782e431 |
hex | 8234222159e9 |
143160422521321 has 2 divisors, whose sum is σ = 143160422521322. Its totient is φ = 143160422521320.
The previous prime is 143160422521261. The next prime is 143160422521411. The reversal of 143160422521321 is 123125224061341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 77591240170921 + 65569182350400 = 8808589^2 + 8097480^2 .
It is a cyclic number.
It is not a de Polignac number, because 143160422521321 - 245 = 107976050432489 is a prime.
It is not a weakly prime, because it can be changed into another prime (143160422524321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71580211260660 + 71580211260661.
It is an arithmetic number, because the mean of its divisors is an integer number (71580211260661).
Almost surely, 2143160422521321 is an apocalyptic number.
It is an amenable number.
143160422521321 is a deficient number, since it is larger than the sum of its proper divisors (1).
143160422521321 is an equidigital number, since it uses as much as digits as its factorization.
143160422521321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 37.
Adding to 143160422521321 its reverse (123125224061341), we get a palindrome (266285646582662).
The spelling of 143160422521321 in words is "one hundred forty-three trillion, one hundred sixty billion, four hundred twenty-two million, five hundred twenty-one thousand, three hundred twenty-one".
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