Base | Representation |
---|---|
bin | 100000100011010011001001… |
… | …001011011000101001101001 |
3 | 200202220021022022100210102212 |
4 | 200203103021023120221221 |
5 | 122231041241112141431 |
6 | 1224252135551134505 |
7 | 42104126115111542 |
oct | 4043231113305151 |
9 | 622807268323385 |
10 | 143163225115241 |
11 | 41686201357981 |
12 | 14081baa514435 |
13 | 61b6307700516 |
14 | 274d1cc17d4c9 |
15 | 118400d8cc72b |
hex | 8234c92d8a69 |
143163225115241 has 2 divisors, whose sum is σ = 143163225115242. Its totient is φ = 143163225115240.
The previous prime is 143163225115219. The next prime is 143163225115297. The reversal of 143163225115241 is 142511522361341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83187168490000 + 59976056625241 = 9120700^2 + 7744421^2 .
It is a cyclic number.
It is not a de Polignac number, because 143163225115241 - 242 = 138765178604137 is a prime.
It is not a weakly prime, because it can be changed into another prime (143163225135241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71581612557620 + 71581612557621.
It is an arithmetic number, because the mean of its divisors is an integer number (71581612557621).
Almost surely, 2143163225115241 is an apocalyptic number.
It is an amenable number.
143163225115241 is a deficient number, since it is larger than the sum of its proper divisors (1).
143163225115241 is an equidigital number, since it uses as much as digits as its factorization.
143163225115241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 172800, while the sum is 41.
Adding to 143163225115241 its reverse (142511522361341), we get a palindrome (285674747476582).
The spelling of 143163225115241 in words is "one hundred forty-three trillion, one hundred sixty-three billion, two hundred twenty-five million, one hundred fifteen thousand, two hundred forty-one".
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