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143163411542521 is a prime number
BaseRepresentation
bin100000100011010011010100…
…010010100011000111111001
3200202220021210022011021120221
4200203103110102203013321
5122231042131323330041
61224252210251020041
742104133540526366
oct4043232422430771
9622807708137527
10143163411542521
114168629760a507
1214082040a3a621
1361b6337214a16
14274d208c2b46d
15118401ee552d1
hex8234d44a31f9

143163411542521 has 2 divisors, whose sum is σ = 143163411542522. Its totient is φ = 143163411542520.

The previous prime is 143163411542423. The next prime is 143163411542527. The reversal of 143163411542521 is 125245114361341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138740953957225 + 4422457585296 = 11778835^2 + 2102964^2 .

It is a cyclic number.

It is not a de Polignac number, because 143163411542521 - 213 = 143163411534329 is a prime.

It is a super-3 number, since 3×1431634115425213 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (143163411542527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71581705771260 + 71581705771261.

It is an arithmetic number, because the mean of its divisors is an integer number (71581705771261).

Almost surely, 2143163411542521 is an apocalyptic number.

It is an amenable number.

143163411542521 is a deficient number, since it is larger than the sum of its proper divisors (1).

143163411542521 is an equidigital number, since it uses as much as digits as its factorization.

143163411542521 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 345600, while the sum is 43.

The spelling of 143163411542521 in words is "one hundred forty-three trillion, one hundred sixty-three billion, four hundred eleven million, five hundred forty-two thousand, five hundred twenty-one".