14318600473 has 4 divisors (see below), whose sum is σ = 14319687888. Its totient is φ = 14317513060.

The previous prime is 14318600441. The next prime is 14318600477. The reversal of 14318600473 is 37400681341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37400681341 = 43 ⋅869783287.

It is a cyclic number.

It is not a de Polignac number, because 14318600473 - 2⁵ = 14318600441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14318600477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523711 + ... + 550372.

It is an arithmetic number, because the mean of its divisors is an integer number (3579921972).

Almost surely, 2^14318600473 is an apocalyptic number.

It is an amenable number.

14318600473 is a deficient number, since it is larger than the sum of its proper divisors (1087415).

14318600473 is a wasteful number, since it uses less digits than its factorization.

14318600473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1087414.

The product of its (nonzero) digits is 48384, while the sum is 37.

The spelling of 14318600473 in words is "fourteen billion, three hundred eighteen million, six hundred thousand, four hundred seventy-three".