Base | Representation |
---|---|
bin | 10100110101100101011… |
… | …001000001111111000001 |
3 | 12001220001022211110202202 |
4 | 110311211121001333001 |
5 | 141430040320420423 |
6 | 3013452313522545 |
7 | 205311304056524 |
oct | 24654531017701 |
9 | 5056038743682 |
10 | 1431925170113 |
11 | 5023044790a9 |
12 | 1b1624a13455 |
13 | a5050aa6289 |
14 | 4d43c5d0bbb |
15 | 273aacb9728 |
hex | 14d65641fc1 |
1431925170113 has 2 divisors, whose sum is σ = 1431925170114. Its totient is φ = 1431925170112.
The previous prime is 1431925170079. The next prime is 1431925170149. The reversal of 1431925170113 is 3110715291341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1319033874064 + 112891296049 = 1148492^2 + 335993^2 .
It is a cyclic number.
It is not a de Polignac number, because 1431925170113 - 210 = 1431925169089 is a prime.
It is not a weakly prime, because it can be changed into another prime (1431925170413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715962585056 + 715962585057.
It is an arithmetic number, because the mean of its divisors is an integer number (715962585057).
Almost surely, 21431925170113 is an apocalyptic number.
It is an amenable number.
1431925170113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431925170113 is an equidigital number, since it uses as much as digits as its factorization.
1431925170113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 38.
The spelling of 1431925170113 in words is "one trillion, four hundred thirty-one billion, nine hundred twenty-five million, one hundred seventy thousand, one hundred thirteen".
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