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14320054321 = 59357241253
BaseRepresentation
bin11010101011000101…
…01011000000110001
31100221222201010120021
431111202223000301
5213311413214241
610324544243441
71014602311336
oct152542530061
940858633507
1014320054321
11608932a841
122937910581
131472a0ba31
1499bbca98d
1558c2a40d1
hex3558ab031

14320054321 has 4 divisors (see below), whose sum is σ = 14320354932. Its totient is φ = 14319753712.

The previous prime is 14320054289. The next prime is 14320054339. The reversal of 14320054321 is 12345002341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9554085025 + 4765969296 = 97745^2 + 69036^2 .

It is a cyclic number.

It is not a de Polignac number, because 14320054321 - 25 = 14320054289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14320054351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61270 + ... + 179983.

It is an arithmetic number, because the mean of its divisors is an integer number (3580088733).

Almost surely, 214320054321 is an apocalyptic number.

It is an amenable number.

14320054321 is a deficient number, since it is larger than the sum of its proper divisors (300611).

14320054321 is an equidigital number, since it uses as much as digits as its factorization.

14320054321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 300610.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 14320054321 its reverse (12345002341), we get a palindrome (26665056662).

The spelling of 14320054321 in words is "fourteen billion, three hundred twenty million, fifty-four thousand, three hundred twenty-one".

Divisors: 1 59357 241253 14320054321