143201240121 has 4 divisors (see below), whose sum is σ = 190934986832. Its totient is φ = 95467493412.

The previous prime is 143201240099. The next prime is 143201240153. The reversal of 143201240121 is 121042102341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 143201240121 - 2⁹ = 143201239609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143201240821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23866873351 + ... + 23866873356.

It is an arithmetic number, because the mean of its divisors is an integer number (47733746708).

Almost surely, 2^143201240121 is an apocalyptic number.

It is an amenable number.

143201240121 is a deficient number, since it is larger than the sum of its proper divisors (47733746711).

143201240121 is an equidigital number, since it uses as much as digits as its factorization.

143201240121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47733746710.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 143201240121 its reverse (121042102341), we get a palindrome (264243342462).

The spelling of 143201240121 in words is "one hundred forty-three billion, two hundred one million, two hundred forty thousand, one hundred twenty-one".