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14320153 is a prime number
BaseRepresentation
bin110110101000…
…001000011001
3222221112120001
4312220020121
512131221103
61230533001
7232501501
oct66501031
928845501
1014320153
1180a0a41
124967161
132c75083
141c8aa01
1513cd01d
hexda8219

14320153 has 2 divisors, whose sum is σ = 14320154. Its totient is φ = 14320152.

The previous prime is 14320133. The next prime is 14320157. The reversal of 14320153 is 35102341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11108889 + 3211264 = 3333^2 + 1792^2 .

It is an emirp because it is prime and its reverse (35102341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14320153 - 25 = 14320121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14320153.

It is not a weakly prime, because it can be changed into another prime (14320157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160076 + 7160077.

It is an arithmetic number, because the mean of its divisors is an integer number (7160077).

Almost surely, 214320153 is an apocalyptic number.

It is an amenable number.

14320153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14320153 is an equidigital number, since it uses as much as digits as its factorization.

14320153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 14320153 is about 3784.1978013841. The cubic root of 14320153 is about 242.8375742842.

Adding to 14320153 its reverse (35102341), we get a palindrome (49422494).

The spelling of 14320153 in words is "fourteen million, three hundred twenty thousand, one hundred fifty-three".