Base | Representation |
---|---|
bin | 1101000001100110000000… |
… | …1101110111110101000111 |
3 | 1212201002002120022120121020 |
4 | 3100121200031313311013 |
5 | 3334113440003323101 |
6 | 50242554233522223 |
7 | 3005442413554041 |
oct | 320314015676507 |
9 | 55632076276536 |
10 | 14321035214151 |
11 | 4621576036696 |
12 | 1733619873373 |
13 | 7cb610a76a23 |
14 | 3771db16ca91 |
15 | 19c7ca163136 |
hex | d0660377d47 |
14321035214151 has 32 divisors (see below), whose sum is σ = 19257476958720. Its totient is φ = 9466350388224.
The previous prime is 14321035214137. The next prime is 14321035214153. The reversal of 14321035214151 is 15141253012341.
14321035214151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14321035214151 - 210 = 14321035213127 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14321035214153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 488807935 + ... + 488837231.
It is an arithmetic number, because the mean of its divisors is an integer number (601796154960).
Almost surely, 214321035214151 is an apocalyptic number.
14321035214151 is a deficient number, since it is larger than the sum of its proper divisors (4936441744569).
14321035214151 is a wasteful number, since it uses less digits than its factorization.
14321035214151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32455.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 14321035214151 its reverse (15141253012341), we get a palindrome (29462288226492).
The spelling of 14321035214151 in words is "fourteen trillion, three hundred twenty-one billion, thirty-five million, two hundred fourteen thousand, one hundred fifty-one".
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