Base | Representation |
---|---|
bin | 1000010101100000111… |
… | …1010101000001010001 |
3 | 111200122212000222002211 |
4 | 2011120033111001101 |
5 | 4321300332142113 |
6 | 145443004112121 |
7 | 13226661516361 |
oct | 2053017250121 |
9 | 450585028084 |
10 | 143214334033 |
11 | 55811837951 |
12 | 2390a235641 |
13 | 106747abcb4 |
14 | 6d084a89a1 |
15 | 3ad3001b3d |
hex | 21583d5051 |
143214334033 has 2 divisors, whose sum is σ = 143214334034. Its totient is φ = 143214334032.
The previous prime is 143214334027. The next prime is 143214334063. The reversal of 143214334033 is 330433412341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113391807169 + 29822526864 = 336737^2 + 172692^2 .
It is a cyclic number.
It is not a de Polignac number, because 143214334033 - 217 = 143214202961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143214333986 and 143214334004.
It is not a weakly prime, because it can be changed into another prime (143214334063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71607167016 + 71607167017.
It is an arithmetic number, because the mean of its divisors is an integer number (71607167017).
Almost surely, 2143214334033 is an apocalyptic number.
It is an amenable number.
143214334033 is a deficient number, since it is larger than the sum of its proper divisors (1).
143214334033 is an equidigital number, since it uses as much as digits as its factorization.
143214334033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 143214334033 its reverse (330433412341), we get a palindrome (473647746374).
The spelling of 143214334033 in words is "one hundred forty-three billion, two hundred fourteen million, three hundred thirty-four thousand, thirty-three".
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