Base | Representation |
---|---|
bin | 11010101011010100… |
… | …10011000011101011 |
3 | 1100222010110200201120 |
4 | 31111222103003223 |
5 | 213312421201410 |
6 | 10325055150323 |
7 | 1014625305411 |
oct | 152552230353 |
9 | 40863420646 |
10 | 14322053355 |
11 | 608a475735 |
12 | 29385153a3 |
13 | 147325b8ac |
14 | 99c18b2b1 |
15 | 58c54b570 |
hex | 355a930eb |
14322053355 has 32 divisors (see below), whose sum is σ = 23137367040. Its totient is φ = 7564515840.
The previous prime is 14322053329. The next prime is 14322053357. The reversal of 14322053355 is 55335022341.
It is not a de Polignac number, because 14322053355 - 223 = 14313664747 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14322053357) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2592286 + ... + 2597804.
It is an arithmetic number, because the mean of its divisors is an integer number (723042720).
Almost surely, 214322053355 is an apocalyptic number.
14322053355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14322053355 is a deficient number, since it is larger than the sum of its proper divisors (8815313685).
14322053355 is a wasteful number, since it uses less digits than its factorization.
14322053355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7171.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 14322053355 its reverse (55335022341), we get a palindrome (69657075696).
The spelling of 14322053355 in words is "fourteen billion, three hundred twenty-two million, fifty-three thousand, three hundred fifty-five".
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