Base | Representation |
---|---|
bin | 10100110101110110011… |
… | …000011100111100000010 |
3 | 12001220210012020001211221 |
4 | 110311312120130330002 |
5 | 141431131304343132 |
6 | 3013540455425254 |
7 | 205321335046123 |
oct | 24656630347402 |
9 | 5056705201757 |
10 | 1432210231042 |
11 | 502440379648 |
12 | 1b16a438522a |
13 | a5097b73396 |
14 | 4d4683d604a |
15 | 273c5d26e97 |
hex | 14d7661cf02 |
1432210231042 has 4 divisors (see below), whose sum is σ = 2148315346566. Its totient is φ = 716105115520.
The previous prime is 1432210231021. The next prime is 1432210231069. The reversal of 1432210231042 is 2401320122341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1023417512881 + 408792718161 = 1011641^2 + 639369^2 .
It is a super-2 number, since 2×14322102310422 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1432210230998 and 1432210231016.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 358052557759 + ... + 358052557762.
Almost surely, 21432210231042 is an apocalyptic number.
1432210231042 is a deficient number, since it is larger than the sum of its proper divisors (716105115524).
1432210231042 is an equidigital number, since it uses as much as digits as its factorization.
1432210231042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 716105115523.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1432210231042 its reverse (2401320122341), we get a palindrome (3833530353383).
The spelling of 1432210231042 in words is "one trillion, four hundred thirty-two billion, two hundred ten million, two hundred thirty-one thousand, forty-two".
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