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1432210231042 = 2716105115521
BaseRepresentation
bin10100110101110110011…
…000011100111100000010
312001220210012020001211221
4110311312120130330002
5141431131304343132
63013540455425254
7205321335046123
oct24656630347402
95056705201757
101432210231042
11502440379648
121b16a438522a
13a5097b73396
144d4683d604a
15273c5d26e97
hex14d7661cf02

1432210231042 has 4 divisors (see below), whose sum is σ = 2148315346566. Its totient is φ = 716105115520.

The previous prime is 1432210231021. The next prime is 1432210231069. The reversal of 1432210231042 is 2401320122341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1023417512881 + 408792718161 = 1011641^2 + 639369^2 .

It is a super-2 number, since 2×14322102310422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1432210230998 and 1432210231016.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 358052557759 + ... + 358052557762.

Almost surely, 21432210231042 is an apocalyptic number.

1432210231042 is a deficient number, since it is larger than the sum of its proper divisors (716105115524).

1432210231042 is an equidigital number, since it uses as much as digits as its factorization.

1432210231042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 716105115523.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1432210231042 its reverse (2401320122341), we get a palindrome (3833530353383).

The spelling of 1432210231042 in words is "one trillion, four hundred thirty-two billion, two hundred ten million, two hundred thirty-one thousand, forty-two".

Divisors: 1 2 716105115521 1432210231042