14322134302051 has 2 divisors, whose sum is σ = 14322134302052. Its totient is φ = 14322134302050.

The previous prime is 14322134302019. The next prime is 14322134302081. The reversal of 14322134302051 is 15020343122341.

14322134302051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14322134302051 - 2⁵ = 14322134302019 is a prime.

It is not a weakly prime, because it can be changed into another prime (14322134302081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161067151025 + 7161067151026.

It is an arithmetic number, because the mean of its divisors is an integer number (7161067151026).

Almost surely, 2^{14322134302051} is an apocalyptic number.

14322134302051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14322134302051 is an equidigital number, since it uses as much as digits as its factorization.

14322134302051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 14322134302051 its reverse (15020343122341), we get a palindrome (29342477424392).

The spelling of 14322134302051 in words is "fourteen trillion, three hundred twenty-two billion, one hundred thirty-four million, three hundred two thousand, fifty-one".