Base | Representation |
---|---|
bin | 11010101011010101… |
… | …00111010101010011 |
3 | 1100222010121220122102 |
4 | 31111222213111103 |
5 | 213312431331103 |
6 | 10325101031015 |
7 | 1014626102501 |
oct | 152552472523 |
9 | 40863556572 |
10 | 14322136403 |
11 | 608a522073 |
12 | 293855546b |
13 | 147328a633 |
14 | 99c1ad671 |
15 | 58c565e88 |
hex | 355aa7553 |
14322136403 has 2 divisors, whose sum is σ = 14322136404. Its totient is φ = 14322136402.
The previous prime is 14322136373. The next prime is 14322136447. The reversal of 14322136403 is 30463122341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14322136403 - 222 = 14317942099 is a prime.
It is a super-2 number, since 2×143221364032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14322136603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161068201 + 7161068202.
It is an arithmetic number, because the mean of its divisors is an integer number (7161068202).
Almost surely, 214322136403 is an apocalyptic number.
14322136403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14322136403 is an equidigital number, since it uses as much as digits as its factorization.
14322136403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 14322136403 its reverse (30463122341), we get a palindrome (44785258744).
The spelling of 14322136403 in words is "fourteen billion, three hundred twenty-two million, one hundred thirty-six thousand, four hundred three".
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