Base | Representation |
---|---|
bin | 10100110101110111001… |
… | …101011010001100000011 |
3 | 12001220211011100100212202 |
4 | 110311313031122030003 |
5 | 141431143333112121 |
6 | 3013542113143415 |
7 | 205321564045400 |
oct | 24656715321403 |
9 | 5056734310782 |
10 | 1432224113411 |
11 | 5024481a0683 |
12 | 1b16a8b5ab6b |
13 | a509a9c40c0 |
14 | 4d46a1ab2a7 |
15 | 273c716a40b |
hex | 14d7735a303 |
1432224113411 has 48 divisors (see below), whose sum is σ = 1799062731648. Its totient is φ = 1130131296000.
The previous prime is 1432224113401. The next prime is 1432224113459. The reversal of 1432224113411 is 1143114222341.
It is not a de Polignac number, because 1432224113411 - 234 = 1415044244227 is a prime.
It is a super-2 number, since 2×14322241134112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1432224113401) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 473774246 + ... + 473777268.
It is an arithmetic number, because the mean of its divisors is an integer number (37480473576).
Almost surely, 21432224113411 is an apocalyptic number.
1432224113411 is a deficient number, since it is larger than the sum of its proper divisors (366838618237).
1432224113411 is a wasteful number, since it uses less digits than its factorization.
1432224113411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4812 (or 4805 counting only the distinct ones).
The product of its digits is 4608, while the sum is 29.
Adding to 1432224113411 its reverse (1143114222341), we get a palindrome (2575338335752).
The spelling of 1432224113411 in words is "one trillion, four hundred thirty-two billion, two hundred twenty-four million, one hundred thirteen thousand, four hundred eleven".
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