Base | Representation |
---|---|
bin | 10100110101110111010… |
… | …001100110101101000001 |
3 | 12001220211020102020120111 |
4 | 110311313101212231001 |
5 | 141431144123310444 |
6 | 3013542152511321 |
7 | 205321606306045 |
oct | 24656721465501 |
9 | 5056736366514 |
10 | 1432225213249 |
11 | 502448881a36 |
12 | 1b16a93ab541 |
13 | a509acba8ac |
14 | 4d46a3b6025 |
15 | 273c72d6234 |
hex | 14d77466b41 |
1432225213249 has 2 divisors, whose sum is σ = 1432225213250. Its totient is φ = 1432225213248.
The previous prime is 1432225213231. The next prime is 1432225213283. The reversal of 1432225213249 is 9423125222341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1204161659649 + 228063553600 = 1097343^2 + 477560^2 .
It is a cyclic number.
It is not a de Polignac number, because 1432225213249 - 211 = 1432225211201 is a prime.
It is a super-2 number, since 2×14322252132492 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1432225214249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716112606624 + 716112606625.
It is an arithmetic number, because the mean of its divisors is an integer number (716112606625).
Almost surely, 21432225213249 is an apocalyptic number.
It is an amenable number.
1432225213249 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432225213249 is an equidigital number, since it uses as much as digits as its factorization.
1432225213249 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 207360, while the sum is 40.
The spelling of 1432225213249 in words is "one trillion, four hundred thirty-two billion, two hundred twenty-five million, two hundred thirteen thousand, two hundred forty-nine".
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