14322444121201 has 4 divisors (see below), whose sum is σ = 14390323003504. Its totient is φ = 14254565238900.

The previous prime is 14322444121199. The next prime is 14322444121243. The reversal of 14322444121201 is 10212144422341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14322444121201 - 2¹ = 14322444121199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14322444121001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33939440835 + ... + 33939441256.

It is an arithmetic number, because the mean of its divisors is an integer number (3597580750876).

Almost surely, 2^{14322444121201} is an apocalyptic number.

It is an amenable number.

14322444121201 is a deficient number, since it is larger than the sum of its proper divisors (67878882303).

14322444121201 is an equidigital number, since it uses as much as digits as its factorization.

14322444121201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67878882302.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 14322444121201 its reverse (10212144422341), we get a palindrome (24534588543542).

The spelling of 14322444121201 in words is "fourteen trillion, three hundred twenty-two billion, four hundred forty-four million, one hundred twenty-one thousand, two hundred one".